add logs

programming_runs/root/for_diagram/humaneval-py_hardest50._reflexion_5_gpt-4_pass_at_k_1_py.jsonl

@@ -1,7 +0,0 @@
-{"task_id": "HumanEval/114", "prompt": "\ndef minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n", "entry_point": "minSubArraySum", "canonical_solution": "    max_sum = 0\n    s = 0\n    for num in nums:\n        s += -num\n        if (s < 0):\n            s = 0\n        max_sum = max(s, max_sum)\n    if max_sum == 0:\n        max_sum = max(-i for i in nums)\n    min_sum = -max_sum\n    return min_sum\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([2, 3, 4, 1, 2, 4]) == 1, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([-1, -2, -3]) == -6\n    assert candidate([-1, -2, -3, 2, -10]) == -14\n    assert candidate([-9999999999999999]) == -9999999999999999\n    assert candidate([0, 10, 20, 1000000]) == 0\n    assert candidate([-1, -2, -3, 10, -5]) == -6\n    assert candidate([100, -1, -2, -3, 10, -5]) == -6\n    assert candidate([10, 11, 13, 8, 3, 4]) == 3\n    assert candidate([100, -33, 32, -1, 0, -2]) == -33\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([-10]) == -10, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([7]) == 7\n    assert candidate([1, -1]) == -1\n", "is_solved": true, "reflections": [], "solution": "\ndef minSubArraySum(nums):\n    \"\"\"\n    Given an array of integers nums, find the minimum sum of any non-empty sub-array\n    of nums.\n    Example\n    minSubArraySum([2, 3, 4, 1, 2, 4]) == 1\n    minSubArraySum([-1, -2, -3]) == -6\n    \"\"\"\n    min_sum = float('inf')\n    for i in range(len(nums)):\n        current_sum = 0\n        for j in range(i, len(nums)):\n            current_sum += nums[j]\n            if current_sum < min_sum:\n                min_sum = current_sum\n    return min_sum"}
-{"task_id": "HumanEval/115", "prompt": "\ndef max_fill(grid, capacity):\n    import math\n    \"\"\"\n    You are given a rectangular grid of wells. Each row represents a single well,\n    and each 1 in a row represents a single unit of water.\n    Each well has a corresponding bucket that can be used to extract water from it, \n    and all buckets have the same capacity.\n    Your task is to use the buckets to empty the wells.\n    Output the number of times you need to lower the buckets.\n\n    Example 1:\n        Input: \n            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n            bucket_capacity : 1\n        Output: 6\n\n    Example 2:\n        Input: \n            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n            bucket_capacity : 2\n        Output: 5\n    \n    Example 3:\n        Input: \n            grid : [[0,0,0], [0,0,0]]\n            bucket_capacity : 5\n        Output: 0\n\n    Constraints:\n        * all wells have the same length\n        * 1 <= grid.length <= 10^2\n        * 1 <= grid[:,1].length <= 10^2\n        * grid[i][j] -> 0 | 1\n        * 1 <= capacity <= 10\n    \"\"\"\n", "entry_point": "max_fill", "canonical_solution": "    return sum([math.ceil(sum(arr)/capacity) for arr in grid])\n", "test": "def check(candidate):\n\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, \"Error\"\n    assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, \"Error\"\n    assert candidate([[0,0,0], [0,0,0]], 5) == 0, \"Error\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n    assert candidate([[1,1,1,1], [1,1,1,1]], 2) == 4, \"Error\"\n    assert candidate([[1,1,1,1], [1,1,1,1]], 9) == 2, \"Error\"\n\n", "is_solved": false, "reflections": [], "solution": "\ndef max_fill(grid, capacity):\n    import math\n    \"\"\"\n    You are given a rectangular grid of wells. Each row represents a single well,\n    and each 1 in a row represents a single unit of water.\n    Each well has a corresponding bucket that can be used to extract water from it, \n    and all buckets have the same capacity.\n    Your task is to use the buckets to empty the wells.\n    Output the number of times you need to lower the buckets.\n\n    Example 1:\n        Input: \n            grid : [[0,0,1,0], [0,1,0,0], [1,1,1,1]]\n            bucket_capacity : 1\n        Output: 6\n\n    Example 2:\n        Input: \n            grid : [[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]]\n            bucket_capacity : 2\n        Output: 5\n    \n    Example 3:\n        Input: \n            grid : [[0,0,0], [0,0,0]]\n            bucket_capacity : 5\n        Output: 0\n\n    Constraints:\n        * all wells have the same length\n        * 1 <= grid.length <= 10^2\n        * 1 <= grid[:,1].length <= 10^2\n        * grid[i][j] -> 0 | 1\n        * 1 <= capacity <= 10\n    \"\"\"\n    total_water = sum(row.count(1) for row in grid)\n    return math.ceil(total_water / capacity)"}
-{"task_id": "HumanEval/116", "prompt": "\ndef sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n    \"\"\"\n", "entry_point": "sort_array", "canonical_solution": "    return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert True, \"This prints if this assert fails 1 (good for debugging!)\"\n    assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]\n    assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]\n    assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]\n    assert candidate([]) == []\n    assert candidate([2,5,77,4,5,3,5,7,2,3,4]) == [2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]\n    assert candidate([3,6,44,12,32,5]) == [32, 3, 5, 6, 12, 44]\n    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n    assert candidate([2,4,8,16,32]) == [2, 4, 8, 16, 32]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True, \"This prints if this assert fails 2 (also good for debugging!)\"\n\n", "solution": "\ndef sort_array(arr):\n    \"\"\"\n    In this Kata, you have to sort an array of non-negative integers according to\n    number of ones in their binary representation in ascending order.\n    For similar number of ones, sort based on decimal value.\n\n    It must be implemented like this:\n    >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]\n    >>> sort_array([-2, -3, -4, -5, -6]) == [-6, -5, -4, -3, -2]\n    >>> sort_array([1, 0, 2, 3, 4]) [0, 1, 2, 3, 4]\n    \"\"\"\n    # Sort the array based on the number of ones in the binary representation and the decimal value\n    return sorted(arr, key=lambda x: (bin(x).count('1'), x))", "is_solved": true, "reflections": ["The implementation is incorrect because it sorts the array based on the number of ones in the binary representation and the decimal value, but it doesn't handle negative numbers correctly. The function sorts negative numbers based on their binary representation, which leads to incorrect results for the test cases involving negative numbers.", "The implementation is incorrect because it sorts the array based on the count of ones in the binary representation of the absolute value of the numbers, rather than the actual value of the numbers. This causes the sorting to be incorrect for certain test cases where the count of ones is the same for different numbers, but their decimal values are not in the correct order.", "The implementation is incorrect because it sorts the array based on the number of ones in the binary representation and the decimal value, but it doesn't handle negative numbers correctly. The function should only accept non-negative integers, but the test cases include negative numbers, which leads to incorrect results.", "The implementation is incorrect because it filters out negative numbers at the beginning, which is not required by the problem statement. As a result, the function only works for non-negative integers and fails for test cases with negative numbers. Additionally, the sorting is based on the number of ones in the binary representation and the decimal value, which is correct, but the filtering of negative numbers causes the wrong output."]}
-{"task_id": "HumanEval/117", "prompt": "\ndef select_words(s, n):\n    \"\"\"Given a string s and a natural number n, you have been tasked to implement \n    a function that returns a list of all words from string s that contain exactly \n    n consonants, in order these words appear in the string s.\n    If the string s is empty then the function should return an empty list.\n    Note: you may assume the input string contains only letters and spaces.\n    Examples:\n    select_words(\"Mary had a little lamb\", 4) ==> [\"little\"]\n    select_words(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n    select_words(\"simple white space\", 2) ==> []\n    select_words(\"Hello world\", 4) ==> [\"world\"]\n    select_words(\"Uncle sam\", 3) ==> [\"Uncle\"]\n    \"\"\"\n", "entry_point": "select_words", "canonical_solution": "    result = []\n    for word in s.split():\n        n_consonants = 0\n        for i in range(0, len(word)):\n            if word[i].lower() not in [\"a\",\"e\",\"i\",\"o\",\"u\"]:\n                n_consonants += 1 \n        if n_consonants == n:\n            result.append(word)\n    return result\n\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"Mary had a little lamb\", 4) == [\"little\"], \"First test error: \" + str(candidate(\"Mary had a little lamb\", 4))      \n    assert candidate(\"Mary had a little lamb\", 3) == [\"Mary\", \"lamb\"], \"Second test error: \" + str(candidate(\"Mary had a little lamb\", 3))  \n    assert candidate(\"simple white space\", 2) == [], \"Third test error: \" + str(candidate(\"simple white space\", 2))      \n    assert candidate(\"Hello world\", 4) == [\"world\"], \"Fourth test error: \" + str(candidate(\"Hello world\", 4))  \n    assert candidate(\"Uncle sam\", 3) == [\"Uncle\"], \"Fifth test error: \" + str(candidate(\"Uncle sam\", 3))\n\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(\"\", 4) == [], \"1st edge test error: \" + str(candidate(\"\", 4))\n    assert candidate(\"a b c d e f\", 1) == [\"b\", \"c\", \"d\", \"f\"], \"2nd edge test error: \" + str(candidate(\"a b c d e f\", 1))\n\n", "solution": "\ndef select_words(s, n):\n    \"\"\"Given a string s and a natural number n, you have been tasked to implement \n    a function that returns a list of all words from string s that contain exactly \n    n consonants, in order these words appear in the string s.\n    If the string s is empty then the function should return an empty list.\n    Note: you may assume the input string contains only letters and spaces.\n    Examples:\n    select_words(\"Mary had a little lamb\", 4) ==> [\"little\"]\n    select_words(\"Mary had a little lamb\", 3) ==> [\"Mary\", \"lamb\"]\n    select_words(\"simple white space\", 2) ==> []\n    select_words(\"Hello world\", 4) ==> [\"world\"]\n    select_words(\"Uncle sam\", 3) ==> [\"Uncle\"]\n    \"\"\"\n    def count_consonants(word):\n        consonants = \"bcdfghjklmnpqrstvwxyzBCDFGHJKLMNPQRSTVWXYZ\"\n        count = 0\n        for char in word:\n            if char in consonants:\n                count += 1\n        return count\n\n    words = s.split()\n    result = [word for word in words if count_consonants(word) == n]\n    return result", "is_solved": true, "reflections": ["The implementation is incorrect because it does not properly handle cases where multiple words have the same number of consonants. In the failed test, both \"apple\" and \"banana\" have 3 consonants, but the expected output is only \"cherry\".", "The implementation is incorrect because there is an indentation issue in the code, causing a syntax error. The count_consonants function is not properly defined, and the code inside it is incorrectly indented. This leads to the \"unexpected indent\" error in the test cases.", "The implementation is incorrect because it calculates the maximum number of consonants in the words and returns an empty list if the given number is greater than the maximum. This causes an error when the input string is empty. Additionally, the function does not correctly filter words with the exact number of consonants, leading to incorrect results in some cases.", "The implementation is incorrect because there is an indentation issue in the code. The `count_consonants` function is not properly defined, causing an \"unexpected indent\" error. This prevents the code from running and passing the test cases."]}
-{"task_id": "HumanEval/118", "prompt": "\ndef get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending doesn't count. Return empty string if you didn't\n    find any vowel met the above condition. \n\n    You may assume that the given string contains English letter only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n", "entry_point": "get_closest_vowel", "canonical_solution": "    if len(word) < 3:\n        return \"\"\n\n    vowels = {\"a\", \"e\", \"i\", \"o\", \"u\", \"A\", \"E\", 'O', 'U', 'I'}\n    for i in range(len(word)-2, 0, -1):\n        if word[i] in vowels:\n            if (word[i+1] not in vowels) and (word[i-1] not in vowels):\n                return word[i]\n    return \"\"\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(\"yogurt\") == \"u\"\n    assert candidate(\"full\") == \"u\"\n    assert candidate(\"easy\") == \"\"\n    assert candidate(\"eAsy\") == \"\"\n    assert candidate(\"ali\") == \"\"\n    assert candidate(\"bad\") == \"a\"\n    assert candidate(\"most\") == \"o\"\n    assert candidate(\"ab\") == \"\"\n    assert candidate(\"ba\") == \"\"\n    assert candidate(\"quick\") == \"\"\n    assert candidate(\"anime\") == \"i\"\n    assert candidate(\"Asia\") == \"\"\n    assert candidate(\"Above\") == \"o\"\n\n    # Check some edge cases that are easy to work out by hand.\n    assert True\n\n", "is_solved": true, "reflections": [], "solution": "\ndef get_closest_vowel(word):\n    \"\"\"You are given a word. Your task is to find the closest vowel that stands between \n    two consonants from the right side of the word (case sensitive).\n    \n    Vowels in the beginning and ending doesn't count. Return empty string if you didn't\n    find any vowel met the above condition. \n\n    You may assume that the given string contains English letter only.\n\n    Example:\n    get_closest_vowel(\"yogurt\") ==> \"u\"\n    get_closest_vowel(\"FULL\") ==> \"U\"\n    get_closest_vowel(\"quick\") ==> \"\"\n    get_closest_vowel(\"ab\") ==> \"\"\n    \"\"\"\n    vowels = \"AEIOUaeiou\"\n    closest_vowel = \"\"\n    for i in range(len(word) - 2, 0, -1):\n        if word[i] in vowels and word[i - 1] not in vowels and word[i + 1] not in vowels:\n            closest_vowel = word[i]\n            break\n    return closest_vowel"}
-{"task_id": "HumanEval/119", "prompt": "\ndef match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n", "entry_point": "match_parens", "canonical_solution": "    def check(s):\n        val = 0\n        for i in s:\n            if i == '(':\n                val = val + 1\n            else:\n                val = val - 1\n            if val < 0:\n                return False\n        return True if val == 0 else False\n\n    S1 = lst[0] + lst[1]\n    S2 = lst[1] + lst[0]\n    return 'Yes' if check(S1) or check(S2) else 'No'\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate(['()(', ')']) == 'Yes'\n    assert candidate([')', ')']) == 'No'\n    assert candidate(['(()(())', '())())']) == 'No'\n    assert candidate([')())', '(()()(']) == 'Yes'\n    assert candidate(['(())))', '(()())((']) == 'Yes'\n    assert candidate(['()', '())']) == 'No'\n    assert candidate(['(()(', '()))()']) == 'Yes'\n    assert candidate(['((((', '((())']) == 'No'\n    assert candidate([')(()', '(()(']) == 'No'\n    assert candidate([')(', ')(']) == 'No'\n    \n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate(['(', ')']) == 'Yes'\n    assert candidate([')', '(']) == 'Yes' \n\n", "solution": "\ndef match_parens(lst):\n    '''\n    You are given a list of two strings, both strings consist of open\n    parentheses '(' or close parentheses ')' only.\n    Your job is to check if it is possible to concatenate the two strings in\n    some order, that the resulting string will be good.\n    A string S is considered to be good if and only if all parentheses in S\n    are balanced. For example: the string '(())()' is good, while the string\n    '())' is not.\n    Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n    Examples:\n    match_parens(['()(', ')']) == 'Yes'\n    match_parens([')', ')']) == 'No'\n    '''\n    s1, s2 = lst\n\n    def is_good(s):\n        stack = []\n        for char in s:\n            if char == '(':\n                stack.append(char)\n            elif stack and stack[-1] == '(':\n                stack.pop()\n            else:\n                return False\n        return not stack\n\n    if is_good(s1 + s2) or is_good(s2 + s1):\n        return 'Yes'\n    else:\n        return 'No'", "is_solved": true, "reflections": ["The implementation is wrong because it only checks if the total count of open and close parentheses is equal in both strings and if one string has more open parentheses and the other has more close parentheses. It doesn't consider the order of the parentheses when concatenating the strings, which is crucial for determining if the resulting string is good or not."]}
-{"task_id": "HumanEval/120", "prompt": "\ndef maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n", "entry_point": "maximum", "canonical_solution": "    if k == 0:\n        return []\n    arr.sort()\n    ans = arr[-k:]\n    return ans\n", "test": "def check(candidate):\n\n    # Check some simple cases\n    assert candidate([-3, -4, 5], 3) == [-4, -3, 5]\n    assert candidate([4, -4, 4], 2) == [4, 4]\n    assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]\n    assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]\n    assert candidate([-123, 20, 0 , 1, 2, -3], 4) == [0, 1, 2, 20]\n    assert candidate([5, 15, 0, 3, -13, -8, 0], 7) == [-13, -8, 0, 0, 3, 5, 15]\n    assert candidate([-1, 0, 2, 5, 3, -10], 2) == [3, 5]\n    assert candidate([1, 0, 5, -7], 1) == [5]\n    assert candidate([4, -4], 2) == [-4, 4]\n    assert candidate([-10, 10], 2) == [-10, 10]\n\n    # Check some edge cases that are easy to work out by hand.\n    assert candidate([1, 2, 3, -23, 243, -400, 0], 0) == []\n\n", "solution": "\ndef maximum(arr, k):\n    \"\"\"\n    Given an array arr of integers and a positive integer k, return a sorted list \n    of length k with the maximum k numbers in arr.\n\n    Example 1:\n\n        Input: arr = [-3, -4, 5], k = 3\n        Output: [-4, -3, 5]\n\n    Example 2:\n\n        Input: arr = [4, -4, 4], k = 2\n        Output: [4, 4]\n\n    Example 3:\n\n        Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n        Output: [2]\n\n    Note:\n        1. The length of the array will be in the range of [1, 1000].\n        2. The elements in the array will be in the range of [-1000, 1000].\n        3. 0 <= k <= len(arr)\n    \"\"\"\n    max_k_elements = sorted(arr, reverse=True)[:k]\n    return sorted(max_k_elements)", "is_solved": true, "reflections": ["The implementation is incorrect because it sorts the array in descending order and then returns the first k elements. However, the problem statement asks for a sorted list of the maximum k numbers, which means the output should be sorted in ascending order. The current implementation returns the maximum k numbers in descending order, causing the failed test cases."]}