'With both together, you can communicate privately and securely with anyone who also has their own key pair.',
uri_id=pubkey.data_b64
qr_str=get_qr_str(uri_id)
qr_path=os.path.join(PATH_QRCODES,name+'.png')
# # what are pub/priv?
# self.status(
# 'I will forge for you two matching keys, part of an "asymmetric" pair.',
# 'Please, watch me work.',
# None,{tw.indent(ART_KEY,' '*5)+'\n'},
# 'I use a high-level cryptographic function from Themis, a well-respected open-source cryptography library.',
# 'I use the iron-clad Elliptic Curve algorthm to generate the asymmetric keypair.',
# '> GenerateKeyPair(KEY_PAIR_TYPE.EC)',
# 3
# )
# self.status(
# None,
# {ART_KEY_PAIR,True}
# ) #,clear=False,indent=10,pause=False)
# self.status(
# None,{ART_KEY_PAIR},
# 'A matching set of keys have been generated.',
# None,{ART_KEY_PAIR2A+'\n\nA matching set of keys have been generated.'},
# '1) First, I have made a "public key" which you can share with anyone:',
# f'{repr(pubkey)}',
# 'This key is a randomly-generated binary string, which acts as your "address" on Komrade.',
# 'By sharing this key with someone, you enable them to write you an encrypted message which only you can read.'
# )
# self.status(
# None,{ART_KEY_PAIR2A},
# f'You can share your public key by copy/pasting it to them over a secure channel (e.g. Signal).',
# 'Or, you can share it as a QR code, especially phone to phone:',
# {qr_str+'\n\n',True,5},
# f'\n\n(If registration is successful, this QR code be saved as an image to your device at: {qr_path}.)'
# )
# private keys
# self.status(None,
# {ART_KEY_PAIR2B},
# 'Second, I have forged a matching "private key":',
# f'{repr(privkey)}',
# 'With it, you can decrypt any message sent to you via your public key.',
# 'You you should never, ever give this key to anyone.',
# 'In fact, this key is so dangerous that I will immediately destroy it by splitting it into two half-keys:'
# )
# self.status(None,
# {ART_KEY_PAIR31A},
# {ART_KEY_PAIR3B+'\n',True},
# 3,'Allow me to explain.',
# '(2A) is a separate encryption key generated by your password.',
# '(2B) is a version of (2) which has been encrypted by (2A).',
# "Because (2) will be destroyed, to rebuild it requires decrypting (2B) with (2A).",
# )
# self.status(
# None,{ART_KEY_PAIR5+'\n'},
# "However, in a final move, I will now destroy (2A), too.",
# None,{ART_KEY_PAIR4Z1+'\n'},
# 'Why? Because now only you can regenerate it, by remembering the password which created it.',
# # None,{ART_KEY_PAIR4Z1+'\n'},
# 'However, this also means that if you lose or forget your password, you\'re screwed.',
# None,{ART_KEY_PAIR4Z2+'\n'},
# "Because without key (2A),you couldn never unlock (2B).",
# None,{ART_KEY_PAIR4Z3+'\n'},
# "And without (2B) and (2A) together, you could never re-assemble the private key of (2).",
# None,{ART_KEY_PAIR4Z42+'\n'},
# "And without (2), you couldn't read messages sent to your public key.",
'We will use the use the iron-clad Elliptic Curve algorthm to generate the keypair, accessed via a high-level cryptography library, Themis (https://github.com/cossacklabs/themis).',
)
self.status(
None,{ART_KEY_PAIR4Z1},
'So choosing a password is an important thing!'
)
ifnotpassphrase:
self.status(
'And it looks like you haven\'t yet chosen a password.',
3,"Don't tell it to me! Never tell it to anyone.",
"Ideally, don't even save it on your computer; just remember it, or write it down on paper.",
"Instead, whisper it to Komrade @Hasher, who scrambles information '1-way', like a blender.",
)
res=self.status(None,
{ART_FROG_BLENDER,True},
"@Keymaker: Go ahead, try it. Type anything to @Hasher.",
quadrismegistus
4 years ago